Michael Carrick refuses to rule out Manchester United title tilt despite 13-point gap

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Марк Эйдельштейн привлек внимание иностранных журналистов на модном показе14:58

I think that was all Jeremy.

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Nothing in the argument required the arc to be a semicircle. If the arc has length xxx times the circumference (where x≤1/2x \leq 1/2x≤1/2), each anchor's event has probability xN−1x^{N-1}xN−1 instead of (1/2)N−1(1/2)^{N-1}(1/2)N−1. Mutual exclusivity still holds because the gap is at least 1−x≥1/21 - x \geq 1/21−x≥1/2 of the circumference, too large for any other anchor's arc to bridge:

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